y = A sin (kx ± ωt)
where two functions take positive and negative signs in the sine parameter to address a particle traveling to the left (positive) and to the right (left). Combining both functions yields a less complex expression:
y = 2 A sin (kx) cos (ωt)
Setting y=0 and focusing on the sin component (x-dependent), we can find the number of nodes;
kx = πn (the sin (kx) needs to be zero to make y=0, and have a constant that also yields zero), or
2πx/λ = nπ
This equation can then be rearranged to find the wavelength based on the number of nodes, n, and having the length of the string:
2L/λ = n
λ = 2L/n
Furthermore, knowing that v = λf, we can interpret the above equation as v = (2L/n)f to find the frequency f;
f = vn/2L
which is dependent of the number of nodes, n and the length of the string, L.
The equation above has the parameter v (wave velocity), which can be obtained through the equation:
The apparatus was set by tying one end of a string to a wave driver, and a mass at the free end. The mass hanged from the edge by a pulley. The driver was then connected to a function generator whose frequency would be controlled.
Mass of string, (kg) = .00237 ± .000005 kg
Length of the string, (m) = 1.98 ± .005 m
Linear density μ, (kg/m) = 0.001197 ± 0.0000039 kg/m
Case A) A total mass of 200 grams was hanged from the free end, and the function generator ran at 3 Volts.
Wave speed v, (m/s) = 40.48 ± 0.083 m/s
Case A) A total mass of 200 grams was hanged from the free end, and the function generator ran at 3 Volts.
Frequency , f (Hz) | 17.900 | 19.700 | 39.100 | 63.100 | 84.200 | 62.200 | 42.200 | 59.900 | 104.500 |
Number of nodes, n | 2 | 2 | 3 | 4 | 5 | 4 | 3 | 4 | 6 |
Length of string, (m) | 0.92±.005 | 1.00±.005 | 1.02±.005 | 0.96±.005 | 0.96±.005 | 1.00±.005 | 0.98±.005 | 1.02±.005 | 1.02±.005 |
Distance between nodes, (m) | 0.92±.005 | 1.00±.005 | 0.51±.005 | 0.32±.005 | 0.24±.005 | 0.330±.005 | 0.49±.005 | 0.34±.005 | 0.20±.005 |
Wavelength λ, (m) | 0.92±.005 | 1.00±.005 | 0.340±.0033 | 0.640±.0033 | 0.384±.0020 | 0.500±.0025 | 0.653±.0033 | 0.510±.0025 | 0.340±.0017 |
Tension T, (N) = mg = (.200 ± .0005 )(9.81) = 1.962 ± 0.0049 N
Wave speed v, (m/s) = 40.48 ± 0.083 m/s
Case B) A mass of 50 grams was hanged from the free end, and the function generator was run at 5 Volts.
Frequency , f (Hz) | 21.000 | 32.000 | 45.000 | 45.900 | 20.400 | 33.100 | 46.300 | 42.400 |
Number of nodes, n | 3 | 4 | 3 | 5 | 3 | 4 | 5 | 5 |
Length of string, (m) | 1.04±.005 | 1.02±.005 | 0.98±.005 | 1.02±.005 | 1.03±.005 | 0.94±.005 | 0.90±.005 | 0.96±.005 |
Distance between nodes, (m) | 0.52±.005 | 0.34±.005 | .49±.005 | .25±.005 | .51±.005 | .31±.005 | .22±.005 | .24±.005 |
Wavelength λ, (m) | 0.693±.0033 | 0.510±.0025 | 0.653±.0033 | 0.408±.0020 | 0.687±.0033 | 0.470±.0025 | 0.360±.0020 | 0.384±.0020 |
Tension T, (N) = mg = (.050 ± .0005 )(9.81) = 0.491 ± 0.0049 N
Wave speed v, (m/s) = 20.2 ± 0.11 m/s
Analysis of Data
Analysis of Data
v = λf and, λ = v/f
n = 2L/ λ
n = 2L/ λ
Case A):
v = 40.48 ± 0.083 m/s
Frequency, f (Hz) | 17.900 | 19.700 | 39.100 | 63.100 | 84.200 | 62.200 | 42.200 | 59.900 | 104.500 |
Wavelength of wave, λ (m) | 2.261±.0046 | 2.055±.0042 | 1.035±.0021 | 0.642±.0013 | 0.4808±.00099 | 0.651±.0013 | 0.959±.0020 | 0.676±.0014 | 0.3874±.00079 |
Value of n | 2.00±.015 | 2.00±.014 | 6.00±.065 | 3.00±.022 | 5.00±.037 | 4.00±.028 | 3.00±.022 | 4.00±.028 | 6.00±.042 |
Case B):
v = 20.2 ± 0.11 m/s
Experimental Wave speed: v = 40.493 m/s
Calculated Wavespeed: v = 40.48 ± 0.083 m/s
Percent Error: 0.032%
Experimental Wave speed: v = 20.189 m/s
Calculated Wave speed: v = 20.2 ± 0.11 m/s
Percent Error: 0.054%
Wave ratios.- Case A : Case B (Experimental):
vA / vb = 40.493 / 20.189 = 2.0057
Wave ratios.- Case A : Case B (Calculated):
vA / vb = 40.48 ± 0.083 / 20.2 ± 0.11 = 2.00 ± .012
The ratios of both experimental and calculated wave speeds turned out to be the same, with an insignificant difference in the order of hundredths.
Case A
The measured frequencies and fn were not the same because they all depended on the number of nodes, n.
There were some results that might have been incorrect, most specificallly when analyzing data from case A. This is due to the string not being well set up. We were having trouble getting a consistent standing wave, so that is why the first wave lenghts of Case A were very off.
Case A
Length of string, (m) | 0.92±.005 | 1.00±.005 | 1.02±.005 | 0.96±.005 | 0.96±.005 | 1.00±.005 | 0.98±.005 | 1.02±.005 | 1.02±.005 |
Number of nodes, n | 2 | 2 | 3 | 4 | 5 | 4 | 3 | 4 | 6 |
f1 | 22.0±.13 | 20.3±.11 | 19.9±.11 | 21.1±.12 | 21.1±.12 | 20.3±.11 | 20.7±.12 | 19.9±.11 | 19.9±.11 |
fn | 44.0±.26 | 40.6±.22 | 59.7±.33 | 84.4±.48 | 105.5±.60 | 81.2±.44 | 62.1±.36 | 79.6±.44 | 119.4±.66 |
The measured frequencies and fn were not the same because they all depended on the number of nodes, n.
There were some results that might have been incorrect, most specificallly when analyzing data from case A. This is due to the string not being well set up. We were having trouble getting a consistent standing wave, so that is why the first wave lenghts of Case A were very off.
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